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Check for Balanced Tree (Function Program)

Given a binary tree, find if it is height balanced or not.  A tree is heigh balanced if difference between heights of left and right subtrees is not more than one for all nodes of tree.    Expected time complexity is O(n).

A height balanced tree
        1
     /     \
   10      39
  /
5

An unbalanced tree
        1
     /    
   10   

  /
5

 

Input:
The task is to complete the method which takes one argument, root of Binary Tree. The struct Node has a data part which stores the data, pointer to left child and pointer to right child.
There are multiple test cases. For each test case, this method will be called individually.

Output:
The function should return true if tree is height balanced, else false.

Constraints:
1 <=T<= 30
1 <=Number of nodes<= 100
1 <=Data of a node<= 1000

Example:
Input:

2
2
1 2 L 2 3 R
4
10 20 L 10 30 R 20 40 L 20 60 R

Output:
0
1

 

There are two test casess.  First case represents a tree with 3 nodes and 2 edges where root is 1, left child of 1 is 2 and right child of 1 is 3.   Second test case represents a tree with 4 edges and 5 nodes.

Note:The Input/Ouput format and Example given are used for system's internal purpose, and should be used by a user for Expected Output only. As it is a function problem, hence a user should not read any input from stdin/console, and should not print anything on stdout/console. The task is to complete the function specified, and not to write the full code.

**For More Examples Use Expected Output**


Contributor: Amit Khandelwal


					   
Result:
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