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Max-Min conversion
     

Given a no N you can perform an operation in it in which you can change a digit 5 to 6 and vice versa. Now your task is to print the sum of the max no and the min no obtained by performing such operations.

Input:
The first line of input contains an integer T denoting the no of test cases. Then T test case follow . Each test case contains a number N.

Output:
For each test case in a new line print the required sum.

Constraints:
1<=T<=100
1<=N<=10000

Example:
Input:

2
35
5
Output:
71
11

Explanation:

For first test case
The max no which can be formed is 36 and the min no which can be formed is 35 itself 
sum : 36+35 = 71

For second test case
sum : 5+6 = 11

** For More Input/Output Examples Use 'Expected Output' option **

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