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Given a boolean matrix of size RxC where each cell contains either 0 or 1, modify it such that if a matrix cell matrix[i][j] is 1 then all the cells in its i^{th} row and j^{th} column will become 1.

**Example 1:**

Input:R = 2, C = 2 matrix[][] = {{1, 0}, {0, 0}}Output:1 1 1 0Explanation:Only cell that has 1 is at (0,0) so all cells in row 0 are modified to 1 and all cells in column 0 are modified to 1.

**Example 2:**

Input:R = 4, C = 3 matrix[][] = {{ 1, 0, 0}, { 1, 0, 0}, { 1, 0, 0}, { 0, 0, 0}}Output:1 1 1 1 1 1 1 1 1 1 0 0Explanation:The position of cells that have 1 in the original matrix are (0,0), (1,0) and (2,0). Therefore, all cells in row 0,1,2 are and column 0 are modified to 1.

**Your Task:**

You dont need to read input or print anything. Complete the function **booleanMatrix()** that takes the matrix as input parameter and modifies it **in-place**.

**Expected Time Complexity:** O(R * C)

**Expected Auxiliary Space:** O(R + C)

**Constraints:**

1 ≤ R, C ≤ 1000

0 ≤ matrix[i][j] ≤ 1

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Boolean Matrix

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