 C++ Nega Bit
##### Submissions: 313   Accuracy: 45.36%   Difficulty: Basic   Marks: 1

Given two integer numbers, whenever the bits of the first number is set i.e. 1, negate the bits of the second number leaving the rest bits of the second number unchanged.

Input:
The first line of input contains integer T denoting the number of test cases. For each test case, there are two integer inputs i.e. f the first number and s the second number whose bits need to be changed according to the set bits
of f

Output:
For each test case, the output is the integer s.

Constraints:
1<=T<=100
1<=f,s<=1000

Example:
Input:
2
2 5
1 3
Output:
7
2

Explanation:

1. 2 is represented as 10 in binary and 5 is represented as 101.Hence negating the 2nd bit of 5 from right, thus the new number becomes 7 i.e. 111.

2.1-1 and 3-11 in binary, thus negating 1st bit of 3 from right we get 10 i.e. 2.

#### ** For More Input/Output Examples Use 'Expected Output' option **

Contributor: Vanshika
Author: Vanshika_pec

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