Given a binary tree, find if it is height balanced or not.
A tree is height balanced if difference between heights of left and right subtrees is not more than one for all nodes of tree.
A height balanced tree
1
/ \
10 39
/
5
An unbalanced tree
1
/
10
/
5
Input:
First line of input contains the number of test cases T. For each test case, there will be only a single line of input which is a string representing the tree as described below:
The values in the string are in the order of level order traversal of the tree where, numbers denotes node values, and a character “N” denotes NULL child.
For example:
For the above tree, the string will be: 1 2 3 N N 4 6 N 5 N N 7 N
Output:
For each testcase, in a new line, print 0 or 1 accordingly.
Your Task:
You don't need to take input. Just complete the function isBalanced() that takes root node as parameter and returns true, if the tree is balanced else returns false.
Constraints:
1 <= T <= 100
1 <= Number of nodes <= 10^{5}
0 <= Data of a node <= 10^{6}
Expected time complexity: O(N)
Expected auxiliary space: O(h) , where h = height of tree
Example:
Input:
3
1 2 N N 3
10 20 30 40 60 N N
4 6 6
Output:
0
1
1
Explanation:
Testcase1: The tree is
1
/
2
\
3
The max difference in height of left subtree and right subtree is 2, which is greater than 1. Hence unbalanced.
Testcase2: The tree is
10
/ \
20 30
/ \
40 60
The max difference in height of left subtree and right subtree is 1. Hence balanced.
Testcase 3: The tree is
10
/ \
6 6
The maximum difference in height of left subtree and right subtree is 0. Hence balanced.
Note: The Input/Ouput format and Example given are used for system's internal purpose, and should be used by a user for Expected Output only. As it is a function problem, hence a user should not read any input from stdin/console. The task is to complete the function specified, and not to write the full code.
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