Given two binary trees with head reference as **T**** **and **S** having at most **N** nodes. The task is to check if S is present as subtree in T.

A subtree of a tree T1 is a tree T2 consisting of a node in T1 and all of its descendants in T1.

**Example:**

**S:** 10

/ \

4 6

/

30

**T:** 26

/ \

10 3

/ \ \

4 6 3

/

30

In above example S is subtree of T.

Please note that subtree has to be having same leaves non leaves.

10

/

20

For example, above tree is not subtree of

10

/ \

20 50

/ \

30 40

But a subtree of

30

/ \

10 50

/

20

**Input Format:**

First line of input contains number of testcases T. For each testcase, there will be 4 lines, first of which containing the number of edges (between two nodes) in the **S** tree. Next line contains N pairs (considering **a** and **b**) with a '**L**' (means node b on left of a) or '**R**' (means node b on right of a) after a and b. The next two lines of every test case contain details of tree **T**

**Output Format:**

For each testcase, there will be a single line containing 0 or 1, depending on the input.

**Your Task:**

Complete the **function isSubtree() **that takes two **nodes **as **parameter **and **returns **true or false.

**Constraints:**

1 <= T <= 30

1 <= N <= 10^{3}

**Example:**

**Input:**

3

1

3 4 L

3

1 2 L 1 3 R 3 4 L

5

26 10 L 10 20 L 10 30 R 20 40 L 20 60 R

5

26 10 L 10 20 L 10 30 R 20 40 L 20 60 R

3

10 4 L 10 6 R 4 30 R

6

26 10 L 26 3 R 10 4 L 10 6 R 6 25 R 3 3 R

**Output:**

1

1

0

**Explanation:**

**Testcase 3:
Structure of tree:**

10 4 L 10 6 R 4 30 R

10 is root node of tree. Left child of 10 is 4 and right child of 10 is 6. Right child of 4 is 30.

Author: mabhinav

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