Geeksforgeeks

Timer is Running

Given a number d, representing the number of digits of a number. Find the total count of positive integers which have at-least one zero in them and consist d or less digits.

**Example 1:**

**Input**: d = 2
**Output:** 9
**Explanation**: There are total 9
positive integers which have
at-least one zero in them
and consist 2 or less digits.

**Example 2:**

**Input: **d = 3
**Output: **180
**Explanation**: There are total 180
positive integers which have
at-least one zero in them
and consist 3 or less digits.

**Your Task: **

You dont need to read input or print anything. Complete the function **findCountUpto() **which takes d as input parameter and returns the total count of positive integers which have at-least one zero in them and consist d or less digits.

**Expected Time Complexity:** O(logn)

**Expected Auxiliary Space:** O(1)

**Constraints:**

1<= d <=15

If you have purchased any course from GeeksforGeeks then please ask your doubt on course discussion forum. You will get quick replies from GFG Moderators there.

jainshubham52535 | 529 |

Pathak1899 | 436 |

yashdip123 | 380 |

kirtidee18 | 377 |

jots62 | 351 |

kirtidee18 | 1057 |

ykaushik | 752 |

aggarwalvatsal5 | 741 |

harbilassingh | 576 |

pmr_3689 | 570 |

blackshadows | 5456 |

Ibrahim Nash | 5450 |

akhayrutdinov | 5111 |

mb1973 | 4976 |

Quandray | 4827 |

Login to report an issue on this page.