Delete Middle of Linked List
Submissions: 11620   Accuracy:


  Difficulty: Easy   Marks: 2

Given a singly linked list, delete middle  of the linked list. For example, if given linked list is 1->2->3->4->5 then linked list should be modified to 1->2->4->5

If there are even nodes, then there would be two middle nodes, we need to delete the second middle element. For example, if given linked list is 1->2->3->4->5->6 then it should be modified to 1->2->3->5->6.

If the input linked list is NULL, then it shoudl remain NULL.

If the input linked list has 1 node, then this node should be deleted and new head should be returned.

You have to complete the method which takes one argument: the head of the linked list. You should not read any input from stdin/console.
The struct Node has a data part which stores the data and a next pointer which points to the next element of the linked list. 
There are multiple test cases. For each test case, this method will be called individually.

Your function should return head  of the modified linked list.  If linked list is empty then it should return NULL.

1 <=T<= 50
1 <=N<= 1000
1 <=value<= 1000


1 2 3 4 5
2 4 6 7 5 1

1 2 4 5
2 4 6 5 1


Note:The Input/Ouput format and Example given are used for system's internal purpose, and should be used by a user for Expected Output only. As it is a function problem, hence a user should not read any input from stdin/console, and should not print anything on stdout/console. The task is to complete the function specified, and not to write the full code.

** For More Input/Output Examples Use 'Expected Output' option **

Contributor: Amit Khandelwal, Harshit Sidhwa
Author: kartik

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