Given a directed graph, the task is to complete the method **isCyclic()** to detect if there is a cycle in the graph or not. You should not read any input from stdin/console. There are multiple test cases. For each test case, this method will be called individually.

**Input:** The first line of the input contains an integer **'T'** denoting the number of test cases. Then **'T'** test cases follow. Each test case consists of two lines. Description of testcases is as follows: The First line of each test case contains two integers **'N' and 'M' ** which denotes the no of vertices and no of edges respectively. The Second line of each test case contains **'M' ** space separated pairs **u** and **v** denoting that there is an uni-directed edge from **u** to **v** .

**Output:**

The method should return **1** if there is a cycle else it should return **0**.

User task:

Since this is a functional program you don't have to worry about input, you just have to complete the function

**Constraints:**

1 <= T <= 100

1<= N,M <= 100

0 <= u,v <= N-1

**Example:
Input:**

3

2 2

0 1 0 0

4 3

0 1 1 2 2 3

4 4

0 1 2 3 3 2

1

0

1

**Explanation:
Testcase 1:** In the above graph there are 2 vertices. The edges are as such among the vertices.

From graph it is clear that it contains cycle.

Author: Shubham Joshi 1

If you have purchased any course from GeeksforGeeks then please ask your doubt on course discussion forum. You will get quick replies from GFG Moderators there.

Login to report an issue on this page.