Timer is Running

Given a Directed Graph. Check whether it contains any cycle or not.

**Input:** The first line of the input contains an integer **'T'** denoting the number of test cases. Then **'T'** test cases follow. Each test case consists of two lines. Description of testcases is as follows: The First line of each test case contains two integers **'N' and 'M' ** which denotes the no of vertices and no of edges respectively. The Second line of each test case contains **'M' ** space separated pairs **u** and **v** denoting that there is an uni-directed edge from **u** to **v** .

**Output:**

The method should return **1** if there is a cycle else it should return **0**.

**User task:**

You don't need to read input or print anything. Your task is to complete the function **isCyclic** which takes the Graph and the number of vertices and inputs and returns true if the given directed graph contains a cycle. Else, it returns false.

**Expected Time Complexity: **O(V + E).

**Expected Auxiliary Space: **O(V).

**Constraints:**

1 <= T <= 1000

1<= N,M <= 1000

0 <= u,v <= N-1

**Example:
Input:**

3

2 2

0 1 0 0

4 3

0 1 1 2 2 3

4 3

0 1 2 3 3 2

1

0

1

**Explanation:
Testcase 1:** In the above graph there are 2 vertices. The edges are as such among the vertices.

From graph it is clear that it contains cycle.

Author: Shubham Joshi 1

If you have purchased any course from GeeksforGeeks then please ask your doubt on course discussion forum. You will get quick replies from GFG Moderators there.

abnandi04 | 801 |

KshamaGupta | 560 |

mummy | 322 |

NikhilGupta0301 | 260 |

jagseersinghbe18cse | 251 |

abnandi04 | 776 |

KshamaGupta | 444 |

mummy | 235 |

srivastavad270 | 223 |

bhavyapratap56 | 206 |

blackshadows | 5362 |

Ibrahim Nash | 5244 |

akhayrutdinov | 5111 |

mb1973 | 4976 |

Quandray | 4748 |

Login to report an issue on this page.