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Find sum of different corresponding bits for all pairs
##### Submissions: 17816   Accuracy: 39.73%   Difficulty: Hard   Marks: 8

We define f (X, Y) as number of different corresponding bits in binary representation of X and Y. For example, f (2, 7) = 2, since binary representation of 2 and 7 are 010 and 111, respectively. The first and the third bit differ, so f (2, 7) = 2.

You are given an array of N integers, A1, A2 ,…, AN. Find sum of f(Ai, Aj) for all pairs (i, j) such that 1 ≤ i, j ≤ N. Return the answer modulo 109+7.

Input:

The first line of each input consists of the test cases. The description of T test cases is as follows:

The first line of each test case contains the size of the array, and the second line has the elements of the array.

Output:

In each separate line print sum of all pairs for (i, j) such that 1 ≤ i, j ≤ N and return the answer modulo 109+7.

Constraints:

1 ≤ T ≤ 70
1 ≤ N ≤ 104
-2,147,483,648 ≤ A[i] ≤ 2,147,483,647

Example:

Input:

2
2
2 4
3
1 3 5

Output:

4
8

Working:

A = [1, 3, 5]

We return

f(1, 1) + f(1, 3) + f(1, 5) +
f(3, 1) + f(3, 3) + f(3, 5) +
f(5, 1) + f(5, 3) + f(5, 5) =

0 + 1 + 1 +
1 + 0 + 2 +
1 + 2 + 0 = 8