Timer is Running

Two of the nodes of a Binary Search Tree (BST) are swapped. Fix (or correct) the BST by swapping them back. Do not change the structure of the tree.

Note: It is guaranteed than the given input will form BST, except for 2 nodes that will be wrong.

Example 1:

Input:
       10
     /    \
    5      8
   / \
  2   20
Output: 1
Explanation:
 

Example 2:

Input:
         11
       /    \
      3      17
       \    /
        4  10
Output: 1

Your Task:
You don't need to take any input. Just complete the function correctBst() that takes root node as parameter. The function should return the root of corrected BST. BST will then be checked by driver code and 0 or 1 will be printed.

Expected Time Complexity : O(n)

Expected Auxiliary Space : O(1)

Constraints:
1 <= Number of nodes <= 1000

** For More Input/Output Examples Use 'Expected Output' option **

Contributor: Saksham Raj Seth
Author: saksham seth


If you have purchased any course from GeeksforGeeks then please ask your doubt on course discussion forum. You will get quick replies from GFG Moderators there.



Need help with your code? Please use ide.geeksforgeeks.org, generate link and share the link here.


to report an issue on this page.