Given a binary tree, the task is to print the nodes in inorder traversal of it. Inorder traversal of below tree is 5 10 1 39
First line of input contains the number of test cases T. For each test case, there will be only a single line of input which is a string representing the tree as described below:
The values in the string are in the order of level order traversal of the tree where, numbers denotes node values, and a character “N” denotes NULL child.
For the above tree, the string will be: 1 2 3 N N 4 6 N 5 N N 7 N
For each test case, in a new line, print the inorder traversal.
This is a function problem. You just need to complete the function inorder() that takes node as parameter and prints the answer. The newline is automatically appended by the driver code.
1 <= T <= 30
1 <= Number of nodes <= 105
1 <= Data of a node <= 105
1 3 2
10 20 30 40 60 50
3 1 2
40 20 60 10 50 30
Testcase1: The tree is
So, the in order would be 3 1 2
Testcase2: The tree is
/ \ /
40 60 50
So, the inorder would be 40 20 60 10 50 30
Note:The Input/Ouput format and Example given are used for system's internal purpose, and should be used by a user for Expected Output only. As it is a function problem, hence a user should not read any input from stdin/console. The task is to complete the function specified, and not to write the full code.
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