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Given a sorted array of** N** numbers, we need to maximize the sum of selected numbers. At each step, you need to select a number A_{i}, delete one occurrence of **A _{i}-1 (if exists), and A_{i}** each from the array. Repeat these steps until the array gets empty. The problem is to maximize the sum of the selected numbers.

**Example 1:**

**â€‹Input :** arr[ ] = {1, 2, 2, 2, 3, 4}
**Output :** 10
**Explanation:**
We select 4, so 4 and 3 are deleted leaving us with {1,2,2,2}.
Then we select 2, so 2 & 1 are deleted. We are left with{2,2}.
We select 2 in next two steps, thus the sum is 4+2+2+2=10.

**â€‹Example 2:**

**Input :** arr[ ] = {1, 2, 3} **
Output :** 4

**Your Task:**

This is a function problem. The input is already taken care of by the driver code. You only need to complete the function **maximizeSum()** that takes an array **(arr)**, sizeOfArray **(n),** and return the maximum sum of the selected numbers. The driver code takes care of the printing.

**Expected Time Complexity:** O(N).

**Expected Auxiliary Space:** O(N).

**Constraints:**

1 ≤ N ≤ 10^{5}

1 ≤ A[i] ≤ 10^{5}

**Note:** Numbers need to be selected from maximum to minimum.

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Maximize the sum of selected numbers from an array to make it empty

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