Starting with any positive integer N, we define the Collatz sequence corresponding to N as the numbers formed by the following operations:

`N` → `N`/2 ( if `N` is even)

`N` → 3`N` + 1 (if `N` is odd)

i.e. If *N* is even, divide it by 2 to get *N* / 2. If *N* is odd, multiply it by 3 and add 1 to obtain 3*N* + 1.

It is conjectured but not yet proven that no matter which positive integer we start with; we always end up with 1.` `

For example, 10 → 5 → 16 → 8 → 4 → 2 → 1

**Note**: The sequence should end at the 1st occurence of integer 1.

The length of the Collatz sequence for some given N is defined as the number of numbers in the sequence starting with N and ending at 1.

Given a positive integer N, the task is to print the maximum Collatz sequence length among all numbers from 1 to N (both included).

**Input: **

The first line of input contains a single integer T denoting the number of test cases. Then T test cases follow. Each test case consists of a single line containing a positive integer N.

**Output:**

Corresponding to each test case, in a new line, print the maximum Collatz sequence length among all numbers from 1 to N (both included).

**Constraints:**

1 ≤ T ≤ 100

1 ≤ N ≤ 1000000

**Example:**

**Input**

2

3

20

**Output**

8

21

**Explanation:**

__For the 1st test case where N = 3__

For N= 3 we need to check sequence length when sequence starts with 1,2, and 3.

when sequence starts with 1, it's : 1 length = 1

when sequence starts with 2, it's : 2->1, length = 2

when sequence starts with 3, it's : 3->10->5->16->8->4->2->1, length = 8, which is max of all.

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