Given a Binary Tree, convert it into its mirror.
Example 1:
Input:
1
/ \
2 3
Output: 2 1 3
Explanation: The tree is
1 (mirror) 1
/ \ => / \
3 2 2 3
The inorder of mirror is 2 1 3
Example 2:
Input:
10
/ \
20 30
/ \
40 60
Output: 30 10 60 20 40
Explanation: The tree is
10 10
/ \ (mirror) / \
20 30 => 30 20
/ \ / \
40 60 60 40
The inroder traversal of mirror is
30 10 60 20 40.
Your Task:
Just complete the function mirror() that takes node as paramter and convert it into its mirror. The printing is done by the driver code only.
Expected Time Complexity: O(N).
Expected Auxiliary Space: O(Height of the Tree).
Constraints:
1 <= Number of nodes <= 100
1 <= Data of a node <= 1000
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Input Format:
The tree in the input is given in the form of a string as described below.
The values in the string are in the order of level order traversal of the tree where, numbers denote node values, and a character “N” denotes NULL child.
For example:
For the above tree, the string will be: 1 2 3 N N 4 6 N 5 N N 7 N
Example:
1 3 2
Input Format:
The tree in the input is given in the form of a string as described below.
The values in the string are in the order of level order traversal of the tree where, numbers denote node values, and a character “N” denotes NULL child.
For example:
For the above tree, the string will be: 1 2 3 N N 4 6 N 5 N N 7 N
Example:
1 3 2