X DAYS

:

HOUR

:

MINS

:

SEC

Copied to Clipboard
Modular Multiplicative Inverse
Easy Accuracy: 48.28% Submissions: 49255 Points: 2

Given two integers ‘a’ and ‘m’. The task is to find the smallest modular multiplicative inverse of ‘a’ under modulo ‘m’.

Example 1:

Input:
a = 3
m = 11
Output: 4
Explanation: Since (4*3) mod 11 = 1, 4
is modulo inverse of 3. One might think,
15 also as a valid output as "(15*3)
mod 11"  is also 1, but 15 is not in
ring {0, 1, 2, ... 10}, so not valid.

Example 2:

Input:
a = 10
m = 17
Output: 12
Explanation: Since (12*10) mod 17 = 1,
12 is the modulo inverse of 10.

function modInverse() that takes a and m as input parameters and returns modular multiplicative inverse of ‘a’ under modulo ‘m’. If the modular multiplicative inverse doesn't exist return -1.

Expected Time Complexity : O(m)
Expected Auxilliary Space : O(1)

Constraints:
1 <= a <= 104
1 <= m <= 104

### Editorial

We strongly recommend solving this problem on your own before viewing its editorial. Do you still want to view the editorial?

#### My Submissions:  