Nth character in Concatenated Decimal String
Submissions: 178   Accuracy:

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  Difficulty: Easy   Marks: 2

If all decimal numbers are concatenated in a string then we will get a string which looks like string P as shown below. We need to tell Nth character of this string.
P = “12345678910111213141516171819202122232425262728293031….”

Input:

The first line of input contains an integer T denoting the number of test cases. Then T test cases follow. The first line of each test case contains the integer N.


Output:

Print the Nth character in the concatenated decimal string for each test case in a new line.


Constraints:

1<= T <=100

1<= N <=100000


Example:

Input:

2

10

11

Output:

1

0

 

** For More Input/Output Examples Use 'Expected Output' option **

Contributor: Sujnesh Mishr
Author: Dharmesh


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