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Given a positive value N, we need to find the count of numbers smaller than and equal to N such that the difference between the number and sum of its digits is greater than or equal to given specific value K.

**Example 1:**

Input:N = 13, K = 2Output:4Explanation: 10, 11, 12 and 13 satisfy the given condition shown below, 10 – sumofdigit(10) = 9 >= 2 11 – sumofdigit(11) = 9 >= 2 12 – sumofdigit(12) = 9 >= 2 13 – sumofdigit(13) = 9 >= 2

â€‹**Example 2:**

**Input**:
N = 10, K = 5
**Output:** 1
**Explanation**: Only 10 satisfies the given
condition as 10 - sumofdigit(10) = 9 >= 5

**Your Task:**

You don't need to read input or print anything. Your task is to complete the function **numberCount() **which takes an integer N and an integer K as inputs and returns the count of numbers less than or equal to N such that the difference between the number and its sum of digits is greater than K.

**Expected Time Complexity: **Log (N).

**Expected Auxiliary Space: **O(1).

**Constraints:**

1 <= N, K <= 10^{9}

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Number and the Digit Sum

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