Geeksforgeeks

Error

×

Leaderboard

Showing:

Handle | Score |
---|---|

@Ibrahim Nash | 6424 |

@blackshadows | 6380 |

@mb1973 | 5704 |

@Quandray | 5245 |

@akhayrutdinov | 5111 |

@saiujwal13083 | 5046 |

@sanjay05 | 3762 |

@kirtidee18 | 3673 |

@mantu_singh | 3532 |

@marius_valentin_dragoi | 3523 |

@sushant_a | 3459 |

Complete Leaderboard | |

Handle | Score |

@cfwong8 | 1160 |

@gurshehzadsingh | 1052 |

@nithinreddy3210 | 801 |

@mohanreddy8847 | 702 |

@balwanyadav34 | 622 |

@satyamchhatrala | 616 |

@pritsahkar2000 | 614 |

@AkashLahoty | 606 |

@amangiri168 | 596 |

@iamchaitanyahegde | 589 |

@iib2019024 | 587 |

Complete Leaderboard |

Every number whose unit’s digit is 3 has a repunit as its multiple. A repunit is a number which has only ones. It is of the form (10^{n} – 1)/9. Example: 3 divides 111, 13 divides 111111.

A positive integer **N** will be given whose unit’s digit is 3. The task is to find the number of 1s in the smallest repunit which is divisible by the given number N.

**Example 1:**

**Input:** N = 3
**Output:** 3
**Explaination:** The number 111 is the first
repunit which is divisible by 3.

**Example 2:**

**Input:** N = 13
**Output:** 6
**Explaination:** The first repunit is 111111
which divisible by 13.

**Your Task:**

You do not need to read input or print anything. Your task is to complete the function **repUnit()** which takes N as input parameter and returns the number of 1 in the smallest repunit which is divisible by N.

**Expected Time Complexity:** O(N)

**Expected Auxiliary Space:** O(1)

**Constraints:**

1 ≤ N ≤ 10^{6}

Login to report an issue on this page.

We strongly recommend solving this problem on your own before viewing its editorial. Do you still want to view the editorial?

YesLoading...

Number of 1's in smallest repunits

...