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Given an array **Arr** of **N** positive integers. Find the number of pairs of integers whose difference is equal to a given number **K**.

**Note:** (a, b) and (b, a) are considered same. Also, same numbers at different indices are considered different.

**Example 1:**

**Input:**
N = 5
Arr[] = {1, 5, 3, 4, 2}
K = 3
**Output:** 2
**Explanation:** There are 2 pairs with difference 3,
the pairs are {1, 4} and {5, 2}

**Example 2:**

**Input:**
N = 6
Arr[] = {8, 12, 16, 4, 0, 20}
K = 4
**Output:** 5
**Explanation:** There are 5 pairs with difference 4,
the pairs are {0, 4}, {4, 8},
{8, 12}, {12, 16} and {16, 20}

**Your Task: **

You don't need to read input or print anything. Your task is to complete the function **countPairsWithDiffK()** which takes the array **arr[],** **n **and** k**** **as inputs and returns an integer denoting the answer.

**Expected Time Complexity:** O(N)

**Expected Auxiliary Space:** O(max(Arr_{i}))

**Constraints:**

1 <= N <= 10^{5}

0 <= K <= 10^{5}

0 <= Arr_{i} <= 10^{5}

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Pairs with difference k

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