Given an integer N, find it's parity.
Parity of a number refers to the number of 1 bits it contains. The number has “odd parity”, if it contains odd number of 1-bits and is “even parity” if it contains even number of 1-bits.
Input:N = 13
Output:oddExplanation:(13)10 = (1101)2 The binary representation
has three 1-bits. So, it's parity is odd.
Input:N = 9
Output:evenExplanation:(9)10 = (1001)2 The binary representation
has two 1-bits. So, it's parity is even.
You don't need to read input or print anything. Your task is to complete the function computeParity() which takes an Integer N as input parameter and returns string "odd" or "even".
Expected Time Complexity: O(log(N)) Expected Auxiliary Space: O(1)