Given a binary tree, print postorder traversal of it. Postorder traversal of below tree is 5 10 39 1
1
/ \
10 39
/
5
Input:
First line of input contains the number of test cases T. For each test case, there will be only a single line of input which is a string representing the tree as described below:
The values in the string are in the order of level order traversal of the tree where, numbers denotes node values, and a character “N” denotes NULL child.
For example:
For the above tree, the string will be: 1 2 3 N N 4 6 N 5 N N 7 N
Output:
For each test case, in a new line, print the postorder traversal.
Your Task:
You don't need to take input. Just complete the function postOrder() that takes node as parameter. The newline is automatically appended by the driver code.
Constraints:
1 <= T <= 100
1 <= Number of nodes <= 100
1 <= Data of a node <= 1000
Example:
Input:
2
19 10 8 11 13
11 15 N 7
Output:
11 13 10 8 19
7 15 11
Explanation:
Testcase1: The tree is
19
/ \
10 8
/ \
11 13
So, the postorder would be 11 13 10 8 19 .
Testcase2: The tree is
11
/
15
/
7
So, the postorder would be 7 15 11.
Note:The Input/Ouput format and Example given are used for system's internal purpose, and should be used by a user for Expected Output only. As it is a function problem, hence a user should not read any input from stdin/console. The task is to complete the function specified, and not to write the full code.
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