Print Linked List elements
Submissions: 29706   Accuracy:


  Difficulty: Basic   Marks: 1
Associated Course(s):   Sudo Placement 2019

You are given the pointer to the head node of a linked list. You have to print all of its elements in order in a single line.


You have to complete a method which takes one argument: the head of the linked list. You should not read any input from stdin/console. The struct Node has a data part which stores the data and a next pointer which points to the next element of the linked list. There are multiple test cases. For each test case, this method will be called individually.


Print the elements of the linked list in a single line separated by a single space.

1 2

1 2

To be used only for expected output :
Here the first line denotes an integer 'T' the no of test cases and the next line denotes 'N' the no of nodes of linked list . Then the line after that contains N space separated integers denoting the values of the nodes of the linked list .


** For More Input/Output Examples Use 'Expected Output' option **

Contributor: Harshit Sidhwa
Author: shubham54

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