Repated Sum and then Multiply
Submissions: 2668   Accuracy:

24.06%

  Difficulty: Basic   Marks: 1

You have to calculate the output in a way that repeated sum of digits until it is before single digit. Multiply those digits which are producing single digit means a final state.

Example-
Lets take 19 as example ,19 breaks into 1+9=10 then 10 breaks into 1+0=1. 1 is a single digit sum.
But we have to multiply the at last step before ( the producer of 1 is 10 so take digits of 10) so 1*0=0
So , output Becomes 0
Lets take another example as 129, so 129 breaks into 1+2+9 =12  breaks into 1+2=3. 3 is single digit sum.
So we take 12 and multiply its digits 1*2=2 
So , output Becomes 2

Input Format-
First Line contains no of test cases by t, and then t inputs.

Output Format-
Every case result should be in new line.

Constraints-
1<=T<=200
1<=n<=4294967296 (232)

Input-
2
19
129

Output-
0
2

** For More Input/Output Examples Use 'Expected Output' option **

Author: Shubham Nagaria


If you have purchased any course from GeeksforGeeks then please ask your doubt on course discussion forum. You will get quick replies from GFG Moderators there.



Need help with your code? Please use ide.geeksforgeeks.org, generate link and share the link here.

to report an issue on this page.