Given a Binary Tree and a sum s, your task is to check whether there is a root to leaf path in that tree with the following sum . You are required to complete the function hasPathSum. You should not read any input from stdin/console. There are multiple test cases. For each test case, this method will be called individually.
Input:
First line of input contains the number of test cases T. For each test case, there will be two lines of input first of which is a string representing the tree as described below:
The values in the string are in the order of level order traversal of the tree where, numbers denotes node values, and a character “N” denotes NULL child.
For example:
For the above tree, the string will be: 1 2 3 N N 4 6 N 5 N N 7 N
Second line contains an integer s.
There are multiple test cases. For each test case, this method will be called individually.
Output:
The function should return the true if such path exist else return false.
Your Task:
You don't need to take input. Just complete the function hasPathSum() which accepts root node of the tree and target sum as a parameter and return a boolean value according to if we can get the sum or not.
Expected Time Complexity: O(N).
Expected Auxiliary Space: O(Height of the Tree).
Constraints:
1 <=T<= 100
1 <=Number of nodes<= 10000
1 <=Data of a node<= 1000
1 <= Sum <= 10^{6}
Example:
Input
2
1 2 3
2
1 2 3
4
Output
0
1
In above example there are two test case where each represents a tree with 3 nodes and 2 edges where root is 1, left child of 1 is 2 and right child of 1 is 3.
Note: The Input/Ouput format and Example given are used for system's internal purpose, and should be used by a user for Expected Output only. As it is a function problem, hence a user should not read any input from stdin/console. The task is to complete the function specified, and not to write the full code.
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