Given a binary tree and an integer S, check whether there is root to leaf path with its sum as S.
Example 1:
Input:
Tree =
1
/ \
2 3
S = 2Output: 0Explanation:
There is no root to leaf path with sum 2.
Example 2:
Input:
Tree =
1
/ \
2 3
S = 4Output: 1Explanation:
The sum of path from leaf node 3 to root 1 is 4.
Your Task:
You dont need to read input or print anything. Complete the function hasPathSum() which takes root node and target sum S as input parameter and returns true if path exists otherwise it returns false.
Expected Time Complexity: O(N) Expected Auxiliary Space: O(height of tree)
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Avoid using static/global variables in coding problems as your code is tested
against multiple test cases and these tend to retain their previous values.
Passing the Sample/Custom Test cases in coding problems does not guarantee the
correctness of code. On submission, your code is tested against multiple test cases
consisting of all possible corner cases and stress constraints.
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