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Given an array **arr[]** of **N** integers. Do the following operation **n-1** times. For every **K ^{th}** operation:

- Right rotate the array clockwise by 1.
- Delete the (
**n-k+1**)last element.^{th}

Now, find the element which is left at last.

**Input:**

The first line of input contains an integer **T **denoting the number of test cases. Then **T **test cases follows. Each test case contains two lines. The first line of each test case contains an integer **N**. Then in the next line are **N **space separated values of the array **arr[]**.

**Output:**

For each test case in a new line print the required result.

**User Task:**

The task is to complete the function **rotateDelete**() which does operations as per given query.

**Constraints:**

1 <= T <= 110

1 <= N <= 10^{6}

1 <= A[i] <= 10^{7}

**Example:
Input**:

2

4

1 2 3 4

6

1 2 3 4 5 6

**Output:**

2

3

**Explanation:
Testcase 2:** A = {1, 2, 3, 4, 5, 6}. Rotate the array clockwise i.e. after rotation the array A = {6, 1, 2, 3, 4, 5} and delete the last element that is {5} so A = {6, 1, 2, 3, 4}. Again rotate the array for the second time and deletes the second last element that is {2} so A = {4, 6, 1, 3}, doing these steps when he reaches 4

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Rotate and delete

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