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Given an integer **N** and an integer **D**, **rotate the binary representation** of the integer **N by D **digits to the **left **as well as **right **and print the **results **in **decimal values** after each of the rotation.

**Note**: Integer N is stored using **16 bits**. i.e. 12 will be stored as 0000.....001100.

**Example 1:**

**Input:**
N = 28, D = 2
**Output:
**112
7
**Explanation**: 28 in Binary is:
000...011100
Rotating left by 2 positions, it becomes
00...1110000 = 112 (in decimal).
Rotating right by 2 positions, it becomes
000...000111 = 7 (in decimal).

â€‹**Example 2:**

**Input**:
N = 29, D = 2
**Output:**
116
16391
**Explanation**: 29 in Binary is:
000...011101
Rotating left by 2 positions, it becomes
00...1110100 = 116 (in decimal).
Rotating right by 2 positions, it becomes
010...000111 = 16391 (in decimal).

**Your Task:**

You don't need to read input or print anything. Your task is to complete the function **rotate() **which takes the integer N and integer D as inputs and returns an array of size 2 where arr[0] = Decimal value after left rotation and arr[1] = Decimal value after right rotation.

**Expected Time Complexity: **O(1).

**Expected Auxiliary Space: **O(1).

**Constraints:**

1 <= N < 2^{16}

1 <= D <= 10^{5}

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