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Given a **Binary Search Tree **and a node value X, find if node with value X is present in the BST or not.

**Example 1:**

**Input:
** 2
\
81
/ \
42 87
/ \ \
45 66 90
x = 87
**Output: **1**
Explanation: **As 87 is present in the
given nodes , so the output will be
1.

**Example 2:**

**Input:
** 6
\
7
/ \
8 9
x = 11
**Output: **0**
Explanation: **As 11 is not present in
he given nodes , so the output will
be 0.

**Your Task:**

You don't need to read input or print anything. Complete the function** search() **which returns **true **if the node with **value x** is **present **in the BST **else returns false**.

**Expected Time Complexity: **O(Height of the BST)

**Expected Auxiliary Space: **O(1).

**Constraints:**

1 <= Number of nodes <= 100

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Search a node in BST

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