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Given a number N.Find if the digit sum(or sum of digits) of N is a Palindrome number or not.

Note:A Palindrome number is a number which stays the same when reversed.Example- 121,131,7 etc.

**Example 1:**

**Input:**
N=56
**Output:**
1
**Explanation:**
The digit sum of 56 is 5+6=11.
Since, 11 is a palindrome number.Thus,
answer is 1.

**Example 2:**

**Input:**
N=98
**Output:**
0
**Explanation:**
The digit sum of 98 is 9+8=17.
Since 17 is not a palindrome,thus, answer
is 0.

**Your Task:**

You don't need to read input or print aything.Your Task is to complete the function **isDigitSumPalindrome()** which takes a number N as input parameter and returns 1 if the Digit sum of N is a palindrome.Otherwise it returns 0.

**Expected Time Complexity:**O(LogN)

**Expected Auxillary Space:**O(1)

**Constraints:**

1<=N<=10^{9}

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Sum of Digit is Pallindrome or not

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