**Compilation/Execution Result:**

Given a Binary Tree where each node has positive and negative values. Convert this to a tree where each node contains the sum of the left and right sub trees in the original tree. The values of leaf nodes are changed to 0.

For example, the following tree

10

/ \

-2 6

/ \ / \

8 -4 7 5

should be changed to

20(4-2+12+6)

/ \

4(8-4) 12(7+5)

/ \ / \

0 0 0 0

**Input:**

The task is to complete the method which takes one argument, root of Binary Tree. There are multiple test cases. For each test case, this method will be called individually.

**Output:**

The function convert the passed tree to its sum tree.

**Constraints:**

1 <=T<= 30

1 <=Number of nodes<= 100

1 <=Data of a node<= 1000

**Example:
Input:**

2

2

3 1 L 3 2 R

4

10 20 L 10 30 R 20 40 L 20 60 R

**Output:**

0 3 0

0 100 0 150 0

The output in this sample test case is Inorder traversal of modified tree.

There are two test casess. First case represents a tree with 3 nodes and 2 edges where root is 3, left child of 3 is 1 and right child of 3 is 2. Second test case represents a tree with 4 edges and 5 nodes.

**Note:**The **Input/Ouput** format and **Example** given are used for system's internal purpose, and should be used by a user for **Expected Output** only. As it is a function problem, hence a user should not read any input from stdin/console. The task is to complete the function specified, and not to write the full code.

Author: kartik

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